olymmath

SHARYGIN 2006 Problem 20

    Four points are given A,B,C,DA, B, C, D . Points A1,B1,C1,D1A_1, B_1, C_1,D_1 are orthocenters of the triangles BCDBCD , CDACDA , DABDAB , ABCABC and A2,A_2, B2B_2 , C2C_2 , D2D_2 are orthocenters of the triangles B1C1D1B_1C_1D_1 , C1D1A1C_1D_1A_1 , D1A1B1D_1A_1B_1 , A1B1C1A_1B_1C_1 etc. Prove that the circles passing through the midpoints of the sides of all the triangles intersect at one point.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator sharygin/2006/p20 · Tag S2F5J1V1CJ · Edit this page on GitHub · Keys: j next, k previous