Home Competitions SE-SKOLORNAS 1979
SE-SKOLORNAS 1979
Swedish Mathematical Competition 1979.
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Problem 1
Solve the equations:
{ x 1 + 2 x 2 + 3 x 3 + ⋯ + ( n − 1 ) x n − 1 + n x n = n 2 x 1 + 3 x 2 + 4 x 3 + ⋯ + n x n − 1 + x n = n − 13 x 1 + 4 x 2 + 5 x 3 + ⋯ + x n − 1 + 2 x n = n − 2 ⋯ ⋯ ⋯ ⋯ ⋅ ⋯ ⋯ ⋯ ⋯ ⋅ ⋯ ⋯ ⋯ ⋯ ⋅ ( n − 1 ) x 1 + n x 2 + x 3 + ⋯ + ( n − 3 ) x n − 1 + ( n − 2 ) x n = 2 n x 1 + x 2 + 2 x 3 + ⋯ + ( n − 2 ) x n − 1 + ( n − 1 ) x n = 1 \left\{ \begin{array}{l}
x_1 + 2 x_2 + 3 x_3 + \cdots + (n-1) x_{n-1} + n x_n = n
2 x_1 + 3 x_2 + 4 x_3 + \cdots + n x_{n-1} + x_n = n-1
3 x_1 + 4 x_2 + 5 x_3 + \cdots + x_{n-1} + 2 x_n = n-2
\cdots \cdots \cdots \cdots\cdot\cdots \cdots \cdots \cdots\cdot\cdots \cdots \cdots \cdots\cdot
(n-1) x_1 + n x_2 + x_3 + \cdots + (n-3) x_{n-1} + (n-2) x_n = 2
n x_1 + x_2 + 2 x_3 + \cdots + (n-2) x_{n-1} + (n-1) x_n = 1
\end{array} \right. { x 1 + 2 x 2 + 3 x 3 + ⋯ + ( n − 1 ) x n − 1 + n x n = n 2 x 1 + 3 x 2 + 4 x 3 + ⋯ + n x n − 1 + x n = n − 13 x 1 + 4 x 2 + 5 x 3 + ⋯ + x n − 1 + 2 x n = n − 2 ⋯⋯⋯⋯ ⋅ ⋯⋯⋯⋯ ⋅ ⋯⋯⋯⋯ ⋅ ( n − 1 ) x 1 + n x 2 + x 3 + ⋯ + ( n − 3 ) x n − 1 + ( n − 2 ) x n = 2 n x 1 + x 2 + 2 x 3 + ⋯ + ( n − 2 ) x n − 1 + ( n − 1 ) x n = 1
Problem 2
Find rational x x x in ( 3 , 4 ) (3,4) ( 3 , 4 ) such that x − 3 \sqrt{x-3} x − 3 and x + 1 \sqrt{x+1} x + 1 are rational.
Problem 3
Express
x 13 + 1 x 13 x^{13} + \frac{1}{x^{13}} x 13 + x 13 1
as a polynomial in y = x + 1 x y = x + \frac{1}{x} y = x + x 1 .
Problem 4
f ( x ) f(x) f ( x ) is continuous on the interval [ 0 , π ] [0, \pi] [ 0 , π ] and satisfies
∫ 0 π f ( x ) d x = 0 , ∫ 0 π f ( x ) cos x d x = 0 \int\limits_0^\pi f(x)dx=0, \int\limits_0^\pi f(x)\cos x dx=0 0 ∫ π f ( x ) d x = 0 , 0 ∫ π f ( x ) cos x d x = 0
Show that f ( x ) f(x) f ( x ) has at least two zeros in the interval ( 0 , π ) (0, \pi) ( 0 , π ) .
Problem 5
Find the smallest positive integer a a a such that for some integers b b b , c c c the polynomial a x 2 − b x + c ax^2 - bx + c a x 2 − b x + c has two distinct zeros in the interval ( 0 , 1 ) (0,1) ( 0 , 1 ) .
Problem 6
Find the sharpest inequalities of the form a ⋅ A B < A G < b ⋅ A B a\cdot AB < AG < b\cdot AB a ⋅ A B < A G < b ⋅ A B and c ⋅ A B < B G < d ⋅ A B c\cdot AB < BG < d\cdot AB c ⋅ A B < B G < d ⋅ A B for all triangles A B C ABC A B C with centroid G G G such that G A > G B > G C GA > GB > GC G A > GB > GC .