olymmath

SE-SKOLORNAS 1977 Problem 3

    Show that the only integral solution to {xy+yz+zx=3n2−1x+y+z=3n\left\{ \begin{array}{l} xy + yz + zx = 3n^2 - 1 x + y + z = 3n \end{array} \right. with x≥y≥zx \geq y \geq z is x=n+1x=n+1 , y=ny=n , z=n−1z=n-1 .

    Dataset text AI-MO AoPS. Quoted with source.

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