Home Competitions SE-SKOLORNAS 1965 Problem 4
SE-SKOLORNAS 1965 Problem 4
Find constants A > B A > B A > B such that f ( 1 1 + 2 x ) f ( x ) \frac{f\left( \frac{1}{1+2x}\right) }{f(x)} f ( x ) f ( 1 + 2 x 1 ) is independent of x x x , where f ( x ) = 1 + A x 1 + B x f(x) = \frac{1 + Ax}{1 + Bx} f ( x ) = 1 + B x 1 + A x for all real x ≠ − 1 B x \ne - \frac{1}{B} x = − B 1 . Put a 0 = 1 a_0 = 1 a 0 = 1 , a n + 1 = 1 1 + 2 a n a_{n+1} = \frac{1}{1 + 2a_n} a n + 1 = 1 + 2 a n 1 . Find an expression for an by considering f ( a 0 ) , f ( a 1 ) , . . . f(a_0), f(a_1), ... f ( a 0 ) , f ( a 1 ) , ... .
Dataset text AI-MO AoPS . Quoted with source.
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