olymmath

SCHWEITZER 2019

Miklós Schweitzer Competition 2019.

Other problems

Problem 1

Prove that if every subspace of a Hausdorff space XX is σ\sigma -compact, then XX is countable.

Problem 2

Let RR be a noncommutative finite ring with multiplicative identity element 11 . Show that if the subring generated by I∪{1}I \cup \{1\} is RR for each nonzero ideal II then RR is simple.

Problem 3

Prove that there are infinitely many integers mm , nn , such that 1<m<n1 < m < n , and the greatest common divisors (m,n)(m, n) , (m,n+1)(m, n+1) , (m+1,n)(m+1, n) and (m+1,n+1)(m+1, n+1) are all greater than n/999\sqrt{n}/999 .

Problem 4

An n×mn \times m matrix is nice if it contains every integer from 11 to mnmn exactly once and 11 is the only entry which is the smallest both in its row and in its column. Prove that the number of n×mn \times m nice matrices is (nm)!n!m!/(n+m−1)!(nm)!n!m!/(n+m-1)! .

Problem 5

Let S⊂RdS \subset \mathbb{R}^d be a convex compact body with nonempty interior. Show that there is an α>0\alpha > 0 such that if S=∩i∈IHiS = \cap_{i \in I} H_i , where II is an index set and (Hi)i∈I(H_i)_{i \in I} are halfspaces, then for any P∈RdP \in \mathbb{R}^d , there is an i∈Ii \in I for which dist(P,Hi)≥αdist(P,S)\mathrm{dist}(P, H_i) \ge \alpha \mathrm{dist}(P, S) .

Problem 6

Let dd be a positive integer and 1<a≤(d+2)/(d+1)1 < a \le (d+2)/(d+1) . For given x0,x1,…,xd∈(0,a−1)x_0, x_1,\dots, x_d \in (0, a-1) , let xk+1=xk(a−xk−d)x_{k+1} = x_k (a - x_{k-d}) , k≥dk \ge d . Prove that lim⁡k→∞xk=a−1\lim_{k \to \infty} x_k = a-1 .

Problem 7

Given a polynomial PP , assume that L={z∈C:∣P(z)∣=1}L = \{z \in \mathbb{C}: |P(z)| = 1\} is a Jordan curve. Show that the zeros of P′P' are in the interior of LL .

Problem 8

Let f:R→Rf: \mathbb{R} \to \mathbb{R} be a measurable function such that f(x+t)−f(x)f(x+t) - f(x) is locally integrable for every tt as a function of xx . Prove that ff is locally integrable.

Problem 10

Let AA and BB be positive self-adjoint operators on a complex Hilbert space HH . Prove that lim sup⁡n→∞∥Anx∥1/n≤lim sup⁡n→∞∥Bnx∥1/n\limsup_{n \to \infty} \|A^n x\|^{1/n} \le \limsup_{n \to \infty} \|B^n x\|^{1/n} holds for every x∈Hx \in H if and only if An≤BnA^n \le B^n for each positive integer nn .