Home Competitions SCHWEITZER 2012 Problem 9
SCHWEITZER 2012 Problem 9
Let D D D be the complex unit disk D = { z ∈ C : ∣ z ∣ < 1 } D=\{z \in \mathbb{C}: |z|<1\} D = { z ∈ C : ∣ z ∣ < 1 } , and 0 < a < 1 0<a<1 0 < a < 1 a real number. Suppose that f : D → C ∖ { 0 } f:D \to \mathbb{C}\setminus \{0\} f : D → C ∖ { 0 } is a holomorphic function such that f ( a ) = 1 f(a)=1 f ( a ) = 1 and f ( − a ) = − 1 f(-a)=-1 f ( − a ) = − 1 . Prove that sup z ∈ D ∣ f ( z ) ∣ ⩾ exp ( 1 − a 2 4 a π ) . \sup_{z \in D} |f(z)| \geqslant \exp\left(\frac{1-a^2}{4a}\pi\right) . z ∈ D sup ∣ f ( z ) ∣ ⩾ exp ( 4 a 1 − a 2 π ) .
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