Home Competitions SCHWEITZER 1992 Problem 6
SCHWEITZER 1992 Problem 6
Let E ⊂ [ 0 , 1 ] E \subset [0,1] E ⊂ [ 0 , 1 ] be a Lebesgue measurable set having Lebesgue measure ∣ E ∣ < 1 2 | E |<\frac{1}{2} ∣ E ∣ < 2 1 . Let h ( s ) = ∫ E ‾ d t ( s − t ) 2 h (s) = \int _ {\overline {E}} \frac{dt}{{(s-t)}^2} h ( s ) = ∫ E ( s − t ) 2 d t where E ‾ = [ 0 , 1 ] \ E \overline {E} = [0,1] \backslash E E = [ 0 , 1 ] \ E . Prove that there is one t ∈ E ‾ t \in \overline {E} t ∈ E for which ∫ E d s h ( s ) ( s − t ) 2 ≤ c ∣ E ∣ 2 \int_E \frac {ds} {h (s) {(s-t)} ^ 2} \leq c {| E |} ^ 2 ∫ E h ( s ) ( s − t ) 2 d s ≤ c ∣ E ∣ 2 with some absolute constant c .
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