olymmath

SCHWEITZER 1985 Problem 9

    Let D={z∈C ⁣:∣z∣<1}D=\{ z\in \mathbb C\colon |z|<1\} and D={w∈C ⁣:∣w∣=1}D=\{ w\in \mathbb C \colon |w|=1\} . Prove that if for a function f ⁣:D×B→Cf\colon D\times B\rightarrow\mathbb C the equality f(az+bb‾z+a‾,aw+bb‾w+a‾)=f(z,w)+f(ba‾,aw+bb‾w+a‾)f\left( \frac{az+b}{\overline{b}z+\overline{a}}, \frac{aw+b}{\overline{b}w+\overline a} \right)=f(z,w)+f\left(\frac{b}{\overline a}, \frac{aw+b}{\overline b w+\overline a} \right) holds for all z∈D,w∈Bz\in D, w\in B and a,b∈C,∣a∣2=∣b∣2+1a, b\in \mathbb C,|a|^2=|b|^2+1 , then there is a function L ⁣:(0,∞)→CL\colon (0, \infty )\rightarrow \mathbb C satisfying L(pq)=L(p)+L(q)   for all  p,q>0L(pq)=L(p)+L(q)\,\,\,\text{for all}\,\, p,q > 0 such that ff can be represented as f(z,w)=L(1−∣z∣2∣w−z∣2)   for all  z∈D,w∈Bf(z,w)=L\left( \frac{1-|z|^2}{|w-z|^2}\right)\,\,\,\text{for all}\,\, z\in D, w\in B . [Gy. Maksa]

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