- Grade 9
Prove, that for every natural exists , such that , where are or
St Petersburg Mathematical Olympiad 2018.
Prove, that for every natural exists , such that , where are or
is odd number. There are numbers on the blackboard. Prove that we can erase one number, such that the sum of all numbers will be not divided any number on the blackboard.
is acuteangled triangle. Variable point lies on segment , and variable point lies on the ray but not segment , such that . is projection of on the . Prove that all points lies on the line.
On the round necklace there are beads, each painted in red or blue. If a bead has adjacent beads painted the same color, it can be repainted (from red to blue or from blue to red). For what for any initial coloring of beads it is possible to make a necklace in which all beads are painted equally?
Can we draw and points , such that , , ?
are odd numbers. Prove, that exists natural that or is divided by .
In square we choose cells. In every chosen cell we draw one arrow from the angle to opposite angle. It is known, that for any two arrows, or the end of one of them coincides with the beginning of the other, or the distance between their ends is at least 2. What is the maximum possible value of ?
Misha came to country with cities, and every cities are connected by the road. Misha want visit some cities, but he doesnt visit one city two time. Every time, when Misha goes from city to city , president of country destroy roads from city (president cant destroy road, where Misha goes). What maximal number of cities Misha can visit, no matter how president does?
Color every vertex of -gon with two colors, such that adjacent vertices have different color. If sum of angles of vertices of first color is same as sum of angles of vertices of second color, than we call -gon as interesting. Convex -gon one vertex is marked. It is known, that if remove any unmarked vertex, then we get interesting -gon. Prove, that if we remove marked vertex, then we get interesting -gon too.
coins lies in the circle. If two neighbour coins lies both head up or both tail up, then we can flip both. How many variants of coins are available that can not be obtained from each other by applying such operations?
is polynomial with integer coefficients, with module not exceeded . has integer root for . Prove that
is inscribed quadrilateral. Line, that perpendicular to intersects segments and and rays at . . is midpoint of . Prove that
The checker moves from the lower left corner of the board to the right top corner, moving at each step one cell to the right or one cell up. Let be the number of paths in which exactly steps the checker take under the diagonal going from the lower left corner to the upper right corner, and is the number of paths in which such steps are exactly . What is more: or ?
Let some line, that is not parallel to the coordinate axes. Find minimal that always exists point with integer coordinates, and distance from to is
Vasya has cards of colors, and there are not more than cards of same color. Prove that he can create square, such that every cards of same color have not common side.
Point lies on the bisector of of acuteangled . Circle with diameter intersects and at points and . Circle, that goes through point and tangent to at intersects line at . Circle, that goes through point and tangent to at intersects line at . Prove, that
has not real roots. Prove that
Regular hexagon is divided to equal rhombuses, with sides, parallels to hexagon sides. On the three sides of the hexagon, among which there are no neighbors, is set directions in order of traversing the hexagon against hour hand. Then, on each side of the rhombus, an arrow directed just as the side of the hexagon parallel to this side. Prove that there is not a closed path going along the arrows.
are positive irrational numbers and for every positive . Prove that
Points lies on the circle . Tangent lines to at and intersects at . -midpoint of . Circle goes through and intersects at and at and . Prove, that tangent lines to at and intersects at point on the segment .