olymmath

RU-SPB 2015 Problem 117

    Let BLBL be angle bisector of acute triangle ABCABC .Point KK choosen on BLBL such that ∡AKC−∡ABC=90º\measuredangle AKC-\measuredangle ABC=90º .point SS lies on the extention of BLBL from LL such that ∡ASC=90º\measuredangle ASC=90º .Point TT is diametrically opposite the point KK on the circumcircle of △AKC\triangle AKC .Prove that STST passes through midpoint of arc ABCABC .(S. Berlov)

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ru-spb/2015/p117 · Tag X7FVYYZ9X7 · Edit this page on GitHub · Keys: j next, k previous