RU-SPB 2009 Problem 97

Discriminants of square trinomials $f(x),g(x),h(x),f(x)+g(x),f(x)+h(x),g(x)+h(x)$ equals $1$ . Prove that $f(x)+h(x)+g(x) \equiv 0$

Dataset text AI-MO AoPS. Quoted with source.

Solutions

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