RU-ALLRUSSIAN 2015 Problem 111

Parallelogram $ABCD$ is such that angle $B < 90$ and $AB<BC$ . Points E and F are on the circumference of $\omega$ inscribing triangle ABC, such that tangents to $\omega$ in those points pass through D. If $\angle EDA= \angle{FDC}$ , find $\angle{ABC}$ .