olymmath

RO-TST 2015 Problem 17

    Let ABCABC be a triangle. Let P1P_1 and P2P_2 be points on the side ABAB such that P2P_2 lies on the segment BP1BP_1 and AP1=BP2AP_1 = BP_2 ; similarly, let Q1Q_1 and Q2Q_2 be points on the side BCBC such that Q2Q_2 lies on the segment BQ1BQ_1 and BQ1=CQ2BQ_1 = CQ_2 . The segments P1Q2P_1Q_2 and P2Q1P_2Q_1 meet at RR , and the circles P1P2RP_1P_2R and Q1Q2RQ_1Q_2R meet again at SS , situated inside triangle P1Q1RP_1Q_1R . Finally, let MM be the midpoint of the side ACAC . Prove that the angles P1RSP_1RS and Q1RMQ_1RM are equal.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ro-tst/2015/p17 · Tag 35T8S3848Y · Edit this page on GitHub · Keys: j next, k previous