olymmath

RO-TST 2005 Problem 12

  • Test 4

Let n≥0n\geq 0 be an integer and let p≡7(mod8)p \equiv 7 \pmod 8 be a prime number. Prove that ∑k=1p−1{k2np−12}=p−12.\sum^{p-1}_{k=1} \left \{ \frac {k^{2^n}}p - \frac 12 \right\} = \frac {p-1}2 .

Călin Popescu

Dataset text AI-MO AoPS. Quoted with source.

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