olymmath

RO-TST 1999 Problem 3

    Prove that for any positive integer nn , the number Sn=(2n+10)⋅22n+(2n+12)⋅22n−2⋅3+⋯+(2n+12n)⋅3nS_n = {2n+1\choose 0}\cdot 2^{2n}+{2n+1\choose 2}\cdot 2^{2n-2}\cdot 3 +\cdots + {2n+1 \choose 2n}\cdot 3^n is the sum of two consecutive perfect squares.

    Dorin Andrica

    Dataset text AI-MO AoPS. Quoted with source.

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