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RO-NMO 2015 Problem 93

  • Grade 9

Let be a point PP in the interior of a triangle ABC.ABC. The lines AP,BP,CPAP,BP,CP meet BC,AC,BC,AC, respectively, ABAB at A1,B1,A_1,B_1, respectively, C1.C_1. If APBA1+APCB1+APAC1=12AABC,\mathcal{A}_{PBA_1} +\mathcal{A}_{PCB_1} +\mathcal{A}_{PAC_1} =\frac{1}{2}\mathcal{A}_{ABC} , show that PP lies on a median of ABC.ABC. A\mathcal{A} denotes area.

Dataset text AI-MO AoPS. Quoted with source.

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