Home Competitions RO-NMO 2005 Problem 101
Let n n n be a positive integer, n ≥ 2 n\geq 2 n ≥ 2 . For each t ∈ R t\in \mathbb{R} t ∈ R , t ≠ k π t\neq k\pi t = k π , k ∈ Z k\in\mathbb{Z} k ∈ Z , we consider the numbers
x n ( t ) = ∑ k = 1 n k ( n − k ) cos ( t k ) and y n ( t ) = ∑ k = 1 n k ( n − k ) sin ( t k ) . x_n(t) = \sum_{k=1}^n k(n-k)\cos{(tk)} \textrm{ and } y_n(t) = \sum_{k=1}^n k(n-k)\sin{(tk)}. x n ( t ) = k = 1 ∑ n k ( n − k ) cos ( t k ) and y n ( t ) = k = 1 ∑ n k ( n − k ) sin ( t k ) .
Prove that if x n ( t ) = y n ( t ) = 0 x_n(t) = y_n(t) =0 x n ( t ) = y n ( t ) = 0 if and only if tan n t 2 = n tan t 2 \tan {\frac {nt}2} = n \tan {\frac t2} tan 2 n t = n tan 2 t .
Constantin Buse
Dataset text AI-MO AoPS . Quoted with source.
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