olymmath

RMM 2025 Problem 3

  • Day 1

Fix an integer n≥3n\geq 3 . Determine the smallest positive integer kk satisfying the following condition:

For any tree TT with vertices v1,v2,…,vnv_{1},v_{2},\ldots ,v_{n} and any pairwise distinct complex numbers z1,z2,…,znz_{1},z_{2},\ldots ,z_{n} , there is a polynomial P(X,Y)P(X,Y) with complex coefficients of total degree at most kk such that for all i≠ji\neq j satisfying 1≤i,j≤n1\leq i,j\leq n , we have P(zi,zj)=0P(z_{i},z_{j}) = 0 if and only if there is an edge in TT joining viv_{i} to vjv_{j} .

Note, for example, that the total degree of the polynomial

9X3Y4+XY5+X6−29X^{3}Y^{4} + XY^{5} + X^{6} - 2

is 7 because 7=3+47 = 3 + 4 .

Each problem is worth 7 marks. Time allowed: 4124\frac{1}{2} hours.

Dataset text NuminaMath olympiads. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator rmm/2025/p3 · Tag 8PRCZ6AP2A · Edit this page on GitHub · Keys: j next, k previous