olymmath

Putnam 2005 A3

  • Session A

Let p(z)p(z) be a polynomial of degree nn all of whose zeros have absolute value 1 in the complex plane. Put g(z)=p(z)/zn/2g(z) = p(z)/z^{n/2}. Show that all zeros of g′(z)=0g'(z) = 0 have absolute value 1.

Curated text Kedlaya Putnam archive. Quoted with source.

Solutions

Human solution Solution 1 by Manjul Bhargava, Kiran Kedlaya and Lenny Ng

The terms of the source let olymmath link to this solution but not copy it. Read the solution (Kedlaya Putnam archive).

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