olymmath

Putnam 1984 B1

  • Session B

Let nn be a positive integer, and define f(n)=1!+2!+…+n!f(n)=1!+2!+\ldots+n! . Find polynomials PP and QQ such that f(n+2)=P(n)f(n+1)+Q(n)f(n)f(n+2)=P(n)f(n+1)+Q(n)f(n) for all n≥1n\ge1 .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator putnam/1984/b1 · Tag 1RS8ZCYD5C · Edit this page on GitHub · Keys: j next, k previous