olymmath

Putnam 1948 B3

  • Session B
  1. If nn is a positive integer, prove that [n+n+1]=[4n+2][\sqrt{n}+\sqrt{n+1}]=[\sqrt{4 n+2}] where [x][x] denotes as usual the greatest integer not exceeding x.x .

Dataset text PutnamGAP. Quoted with source.

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