olymmath

Putnam 1947 B4

  • Session B

Given P(z)=z2+az+b,P(z)= z^2 +az +b, where a,b∈C.a,b \in \mathbb{C}. Suppose that ∣P(z)∣=1|P(z)|=1 for every complex number zz with ∣z∣=1.|z|=1. Prove that a=b=0.a=b=0.

Dataset text AI-MO AoPS. Quoted with source.

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