olymmath

OPM 1999

Portuguese Mathematical Olympiad 1999.

Official paper

The official paper in 2 languages

Portuguese (day1) · Portuguese (day2)

Final day 1

Problem 3

  • Final day 1

If two parallel chords of a circumference, 1010 mm and 1414 mm long, with distance 66 mm from each other, how long is the chord equidistant from these two?

Answer, solutions and source

Final day 2

Problem 4

  • Final day 2

Given a number, we calculate its square and add 11 to the sum of the digits in this square, obtaining a new number. If we start with the number 77 we will obtain, in the first step, the number 1+(4+9)=141+(4+9)=14 , since 72=497^2 = 49 . What number will we obtain in the 19991999 th step?

Answer, solutions and source

Problem 5

  • Final day 2

Each of the numbers a1,...,ana_1,...,a_n is equal to 11 or −1-1 . If a1a2+a2a3+⋅⋅⋅+an−1an+ana1=0a_1a_2 + a_2a_3 + ··· + a_{n-1}a_n + a_na_1 = 0 , proves that nn is divisible by 44 .

Answer, solutions and source

Problem 6

  • Final day 2

In the triangle [ABC],D[ABC], D is the midpoint of [AB][AB] and EE is the trisection point of [BC][BC] closer to CC . If ∠ADC=∠BAE\angle ADC= \angle BAE , find the measue of ∠BAC\angle BAC .

Answer, solutions and source