olymmath

PL-OM 2012

Polish Mathematical Olympiad 2012.

Other problems

Problem 1

Decide, whether exists positive rational number ww , which isn't integer, such that www^w is a rational number.

Problem 2

Determine all pairs (m,n)(m, n) of positive integers, for which cube KK with edges of length nn , can be build in with cuboids of shape m×1×1m \times 1 \times 1 to create cube with edges of length n+2n + 2 , which has the same center as cube KK .

Problem 3

Triangle ABCABC with AB=ACAB = AC is inscribed in circle oo . Circles o1o_1 and o2o_2 are internally tangent to circle oo in points PP and QQ , respectively, and they are tangent to segments ABAB and ACAC , respectively, and they are disjoint with the interior of triangle ABCABC . Let mm be a line tangent to circles o1o_1 and o2o_2 , such that points PP and QQ lie on the opposite side than point AA . Line mm cuts segments ABAB and ACAC in points KK and LL , respectively. Prove, that intersection point of lines PKPK and QLQL lies on bisector of angle BACBAC .

Problem 4

nn players ( n≥4n \ge 4 ) took part in the tournament. Each player played exactly one match with every other player, there were no draws. There was no four players (A,B,C,D)(A, B, C, D) , such that AA won with BB , BB won with CC , CC won with DD and DD won with AA . Determine, depending on nn , maximum number of trios of players (A,B,C)(A, B, C) , such that AA won with BB , BB won with CC and CC won with AA . (Attention: Trios (A,B,C)(A, B, C) , (B,C,A)(B, C, A) and (C,A,B)(C, A, B) are the same trio.)

Problem 5

Point OO is a center of circumcircle of acute triangle ABCABC , bisector of angle BACBAC cuts side BCBC in point DD . Let MM be a point such that, MC⊥BCMC \perp BC and MA⊥ADMA \perp AD . Lines BMBM and OAOA intersect in point PP . Show that circle of center in point PP passing through a point AA is tangent to line BCBC .

Problem 6

Show that for any positive real numbers a,b,ca, b, c true is inequality: (a−bc)2+(b−ca)2+(c−ab)2≥22(a−bc+b−ca+c−ab)\left(\frac{a - b}{c}\right)^2 + \left(\frac{b - c}{a}\right)^2 + \left(\frac{c - a}{b}\right)^2 \ge 2\sqrt{2}\left(\frac{a - b}{c} + \frac{b - c}{a} + \frac{c - a}{b} \right) .