olymmath

PL-OM 1992 Problem 1

    Segments ACAC and BDBD meet at PP , and ∣PA∣=∣PD∣|PA| = |PD| , ∣PB∣=∣PC∣|PB| = |PC| . OO is the circumcenter of the triangle PABPAB . Show that OPOP and CDCD are perpendicular.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator pl-om/1992/p1 · Tag KHP4KCD5F7 · Edit this page on GitHub · Keys: j next, k previous