PL-OM 1986 Problem 5
There is a chess tournament with players ( ). There is at most one match between each pair of players. If it is not possible to find three players who all play each other, show that there are at most matches. Conversely, show that if there are at most matches, then it is possible to arrange them so that we cannot find three players who all play each other.
Dataset text AI-MO AoPS. Quoted with source.
Solutions
No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.
Similar problems
These problems have the most words in common with this statement.