olymmath

PE-MO 2013 Problem 2

    The positive integers a,b,ca, b, c are such that gcd  (a,b,c)=1,gcd \,\, (a, b, c) = 1, gcd   (a,b+c)>1,gcd \,\,\,(a, b + c) > 1, gcd   (b,c+a)>1,gcd \,\,\,(b, c + a) > 1, gcd   (c,a+b)>1.gcd \,\,\,(c, a + b) > 1. Determine the smallest possible value of a+b+ca + b + c .

    Clarification: gcd stands for greatest common divisor.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator pe-mo/2013/p2 · Tag 5F5YKZYSMT · Edit this page on GitHub · Keys: j next, k previous