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PAMO 2023 Problem 6

  • Day 2

Let ABCABC be an acute triangle with AB<ACAB<AC . Let D,E,D, E, and FF be the feet of the perpendiculars from A,B,A, B, and CC to the opposite sides, respectively. Let PP be the foot of the perpendicular from FF to line DEDE . Line FPFP and the circumcircle of triangle BDFBDF meet again at QQ . Show that ∠PBQ=∠PAD\angle PBQ = \angle PAD .

Dataset text AI-MO AoPS. Quoted with source.

Official text: Pan-African Mathematics Olympiad 2023 official paper, page 1.

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