olymmath

PAMO 2001 Problem 3

  • Day 1

Let ABCABC be an equilateral triangle and let P0P_0 be a point outside this triangle, such that △AP0C\triangle{AP_0C} is an isoscele triangle with a right angle at P0P_0 . A grasshopper starts from P0P_0 and turns around the triangle as follows. From P0P_0 the grasshopper jumps to P1P_1 , which is the symmetric point of P0P_0 with respect to AA . From P1P_1 , the grasshopper jumps to P2P_2 , which is the symmetric point of P1P_1 with respect to BB . Then the grasshopper jumps to P3P_3 which is the symmetric point of P2P_2 with respect to CC , and so on. Compare the distance P0P1P_0P_1 and P0PnP_0P_n . n∈Nn \in N .

Dataset text AI-MO AoPS. Quoted with source.

Official text: Pan-African Mathematics Olympiad 2001 official paper, page 1.

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