olymmath

NZ-NZMO 2023 Problem 6

    Let triangle ABCABC be right-angled at AA . Let DD be the point on ACAC such that BDBD bisects angle ∠ABC\angle ABC . Prove that BC−BD=2ABBC - BD = 2AB if and only if 1BD−1BC=12AB\frac{1}{BD} - \frac{1}{BC} = \frac{1}{2AB} .

    Dataset text NuminaMath olympiads. Quoted with source.

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