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NMC 1999 Problem 1

  • Answer

The function ff is defined for non-negative integers and satisfies the condition

f(n)={f(f(n+11)), if n≤1999n−5, if n>1999f(n)= \begin{cases}f(f(n+11)), & \text { if } n \leq 1999 \\ n-5, & \text { if } n>1999\end{cases}

Find all solutions of the equation f(n)=1999f(n)=1999.

Dataset text NuminaMath olympiads. Quoted with source.

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1999=f(6n), \text{ if and only if } n=1,2, \ldots, 334

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