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NMC 1993 Problem 2

  • Answer

A hexagon is inscribed in a circle of radius rr. Two of the sides of the hexagon have length 1, two have length 2 and two have length 3. Show that rr satisfies the equation

2r3−7r−3=02 r^{3}-7 r-3=0

Figure 5.

Dataset text NuminaMath olympiads. Quoted with source.

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2 r^{3}-7 r-3=0

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