olymmath

NO-ABEL 2017 Problem 4

    Let a>0a > 0 and 0<α<π0 < \alpha <\pi be given. Let ABCABC be a triangle with BC=aBC = a and ∠BAC=α\angle BAC = \alpha , and call the cicumcentre OO , and the orthocentre HH . The point PP lies on the ray from AA through OO . Let SS be the mirror image of PP through ACAC , and TT the mirror image of PP through ABAB . Assume that SATHSATH is cyclic. Show that the length APAP depends only on aa and α\alpha .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator no-abel/2017/p4 · Tag DG5D2J05E8 · Edit this page on GitHub · Keys: j next, k previous