olymmath

NL-NWO 2016 Problem 2

    For an integer n≥1n \ge 1 we consider sequences of 2n2n numbers, each equal to 0,−10, -1 or 11 . The sum product value of such a sequence is calculated by first multiplying each pair of numbers from the sequence, and then adding all the results together. For example, if we take n=2n = 2 and the sequence 0,1,1,−10,1, 1, -1 , then we find the products 0⋅1,0⋅1,0⋅−1,1⋅1,1⋅−1,1⋅−10\cdot 1, 0\cdot 1, 0\cdot -1, 1\cdot 1, 1\cdot -1, 1\cdot -1 . Adding these six results gives the sum product value of this sequence: 0+0+0+1+(−1)+(−1)=−10+0+0+1+(-1)+(-1) = -1 . The sum product value of this sequence is therefore smaller than the sum product value of the sequence 0,0,0,00, 0, 0, 0 , which equals 00 . Determine for each integer n≥1n \ge 1 the smallest sum product value that such a sequence of 2n2n numbers could have.

    Attention: you are required to prove that a smaller sum product value is impossible.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator nl-nwo/2016/p2 · Tag SM5E6C49JK · Edit this page on GitHub · Keys: j next, k previous