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NL-NWO 2005 Problem 2

    Let P1P2P3…P12P_1P_2P_3\dots P_{12} be a regular dodecagon. Show that ∣P1P2∣2+∣P1P4∣2+∣P1P6∣2+∣P1P8∣2+∣P1P10∣2+∣P1P12∣2\left|P_1P_2\right|^2 + \left|P_1P_4\right|^2 + \left|P_1P_6\right|^2 + \left|P_1P_8\right|^2 + \left|P_1P_{10}\right|^2 + \left|P_1P_{12}\right|^2 is equal to ∣P1P3∣2+∣P1P5∣2+∣P1P7∣2+∣P1P9∣2+∣P1P11∣2.\left|P_1P_3\right|^2 + \left|P_1P_5\right|^2 + \left|P_1P_7\right|^2 + \left|P_1P_9\right|^2 + \left|P_1P_{11}\right|^2.

    Dataset text AI-MO AoPS. Quoted with source.

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