olymmath

NL-NWO 1989 Problem 2

    Given is a square ABCDABCD with E∈BCE \in BC , arbitrarily. On CDCD lies the point FF is such that ∠EAF=45o\angle EAF = 45^o . Prove that EFEF is tangent to the circle with center AA and radius ABAB .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator nl-nwo/1989/p2 · Tag CASTVB5S60 · Edit this page on GitHub · Keys: j next, k previous