olymmath

NL-NWO 1986

Dutch Mathematical Olympiad Final 1986.

Other problems

Problem 1

f(x)=12x+919x+86, x≠−8619f(x) = \frac{12x+9}{19x+86}, \, x \ne -\frac{86}{19} Prove that ∃!  xo∈R  ∀h1,h2∈R[f(x0+h1)f(x0−h1)=f(x0+h2)f(x0−h2)]\exists ! \,\, {x_o \in R} \,\, \forall h_1,h_2 \in R [f(x_0+h_1)f(x_0-h_1)=f(x_0+h_2)f(x_0-h_2)] , and calculate x0x_0 .

Problem 2

Prove that for all positive integers nn holds that 12⋅3+13⋅4+...+1(2n−1)⋅2n=1n+1+1n+2+...+12n\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+...+\frac{1}{(2n-1) \cdot 2n}=\frac{1}{n+1}+\frac{1}{n+2}+...+\frac{1}{2n}

Problem 3

The following apply: a,b,c,d≥0a,b,c,d \ge 0 and abcd=1abcd=1 Prove that a2+b2+c2+d2+ab+ac+ad+bc+bd+cd≥10a^2+b^2+c^2+d^2+ab+ac+ad+bc+bd+cd \ge 10

Problem 4

The lines aa and bb are parallel and the point AA lies on aa . One chooses one circle γ\gamma through A tangent to bb at BB . aa intersects γ\gamma for the second time at TT . The tangent line at TT of γ\gamma is called tt . Prove that independently of the choice of γ\gamma , there is a fixed point PP such that BTBT passes through PP . Prove that independently of the choice of γ\gamma , there is a fixed circle δ\delta such that tt is tangent to δ\delta .