olymmath

OMM 2015 Problem 3

    Let N={1,2,3,...}\mathbb{N} =\{1, 2, 3, ...\} be the set of positive integers. Let f:N→Nf : \mathbb{N} \rightarrow \mathbb{N} be a function that gives a positive integer value, to every positive integer. Suppose that ff satisfies the following conditions: f(1)=1f(1)=1 f(a+b+ab)=a+b+f(ab)f(a+b+ab)=a+b+f(ab) Find the value of f(2015)f(2015) Proposed by Jose Antonio Gomez Ortega

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator mx-omm/2015/p3 · Tag NMGED3JSJJ · Edit this page on GitHub · Keys: j next, k previous