olymmath

OMM 2012 Problem 4

    The following process is applied to each positive integer: the sum of its digits is subtracted from the number, and the result is divided by 99 . For example, the result of the process applied to 938938 is 102102 , since 938−(9+3+8)9=102.\frac{938-(9 + 3 + 8)}{9} = 102. Applying the process twice to 938938 the result is 1111 , applied three times the result is 11 , and applying it four times the result is 00 . When the process is applied one or more times to an integer nn , the result is eventually 00 . The number obtained before obtaining 00 is called the house of nn .

    How many integers less than 2600026000 share the same house as 20122012 ?

    Dataset text AI-MO AoPS. Quoted with source.

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