olymmath

MK-MO 2022

North Macedonia national mathematics olympiad 2022.

Other problems

Problem 1

Let (xn)n=1∞(x_n)_{n=1}^\infty be a sequence defined recursively with: x1=2x_1=2 and xn+1=xn(xn+n)n+1x_{n+1}=\frac{x_n(x_n+n)}{n+1} for all n≥1n \ge 1 . Prove that n(n+1)>(x1+x2+…+xn)2xn+1.n(n+1) >\frac{(x_1+x_2+ \ldots +x_n)^2}{x_{n+1}}. Proposed by Nikola Velov

Problem 2

Let ABCDABCD be cyclic quadrilateral and EE the midpoint of ACAC . The circumcircle of △CDE\triangle CDE intersect the side BCBC at FF , which is different from CC . If B′B' is the reflection of BB across FF , prove that EFEF is tangent to the circumcircle of △B′DF\triangle B'DF .

Proposed by Nikola Velov

Problem 3

The sequence (an)n≥1∞(a_n)_{n \ge 1}^\infty is given by: a1=2a_1=2 and an+1=an2+ana_{n+1}=a_n^2+a_n for all n≥1n \ge 1 . For an integer m≥2m \ge 2 , L(m)L(m) denotes the greatest prime divisor of mm . Prove that there exists some kk , for which L(ak)>10001000L(a_k) > 1000^{1000} .

Proposed by Nikola Velov

Problem 4

Sofia and Viktor are playing the following game on a 2022×20222022 \times 2022 board:

  • Firstly, Sofia covers the table completely by dominoes, no two are overlapping and all are inside the table;
  • Then Viktor without seeing the table, chooses a positive integer nn ;
  • After that Viktor looks at the table covered with dominoes, chooses and fixes nn of them;
  • Finally, Sofia removes the remaining dominoes that aren't fixed and tries to recover the table with dominoes differently from before. If she achieves that, she wins, otherwise Viktor wins. What is the minimum number nn for which Viktor can always win, no matter the starting covering of dominoes.

Proposed by Viktor Simjanoski

Problem 5

An acute △ABC\triangle ABC with circumcircle Γ\Gamma is given. II and IaI_a are the incenter and A−A- excenter of △ABC\triangle ABC respectively. The line AIAI intersects Γ\Gamma again at DD and A′A' is the antipode of AA with respect to Γ\Gamma . XX and YY are point on Γ\Gamma such that ∠IXD=∠IaYD=90∘\angle IXD = \angle I_aYD = 90^\circ . The tangents to Γ\Gamma at XX and YY intersect in point ZZ . Prove that A′,DA', D and ZZ are collinear.

Proposed by Nikola Velov