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MEMO 2023 I3

    Let ABCABC be a triangle with incenter II. The incircle ω\omega of ABCABC is tangent to the line BCBC at point DD. Denote by EE and FF the points satisfying AI∥BE∥CFAI \parallel BE \parallel CF and ∠BEI=∠CFI=90∘\angle BEI = \angle CFI = 90^\circ. Lines DEDE and DFDF intersect ω\omega again at points E′E' and F′F', respectively. Prove that E′F′⊥AIE'F' \perp AI.

    Official text Middle European Mathematical Olympiad 2023 official paper, page 1. Quoted with source.

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