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MEMO 2016 Problem 6

    Let ABCABC be a triangle for which AB≠ACAB \neq AC . Points KK , LL , MM are the midpoints of the sides BCBC , CACA , ABAB . The incircle of ABCABC with center II is tangent to BCBC in DD . A line passing through the midpoint of IDID perpendicular to IKIK meets the line LMLM in PP .

    Prove that ∠PIA=90∘\angle PIA = 90 ^{\circ} .

    Dataset text AI-MO AoPS. Quoted with source.

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