olymmath

OMCPLP 2018 Problem 3

  • Day 1

For each positive integer nn , let S(n)S(n) be the sum of the digits of nn . Determines the smallest positive integer aa such that there are infinite positive integers nn for which you have S(n)−S(n+a)=2018S (n) -S (n + a) = 2018 .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator lusophon/2018/p3 · Tag YNFBZ6EWSN · Edit this page on GitHub · Keys: j next, k previous