olymmath

OMCPLP 2015

Lusophon Mathematical Olympiad 2015.

Day 1

Problem 1

  • Day 1

In a triangle ABC,LABC, L and KK are the points of intersections of the angle bisectors of ∠ABC\angle ABC and ∠BAC\angle BAC with the segments ACAC and BCBC , respectively. The segment KLKL is angle bisector of ∠AKC\angle AKC , determine ∠BAC\angle BAC .

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Problem 2

  • Day 1

Determine all ten-digit numbers whose decimal a0a1a2a3a4a5a6a7a8a9‾\overline{a_0a_1a_2a_3a_4a_5a_6a_7a_8a_9} is given by such that for each integer jj with 0≤j≤9,aj0\le j \le 9, a_j is equal to the number of digits equal to jj in this representation. That is: the first digit is equal to the amount of " 00 " in the writing of that number, the second digit is equal to the amount of " 11 " in the writing of that number, the third digit is equal to the amount of " 22 " in the writing of that number, ... , the tenth digit is equal to the number of " 99 " in the writing of that number.

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Problem 3

  • Day 1

In the center of a square is a rabbit and at each vertex of this even square, a wolf. The wolves only move along the sides of the square and the rabbit moves freely in the plane. Knowing that the rabbit move at a speed of 1010 km / h and that the wolves move to a maximum speed of 1414 km / h, determine if there is a strategy for the rabbit to leave the square without being caught by the wolves.

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Day 2

Problem 4

  • Day 2

Let aa be a real number, such that a≠0,a≠1,a≠−1a\ne 0, a\ne 1, a\ne -1 and m,n,p,qm,n,p,q be natural numbers . Prove that if am+an=ap+aqa^m+a^n=a^p+a^q and a3m+a3n=a3p+a3qa^{3m}+a^{3n}=a^{3p}+a^{3q} , then m⋅n=p⋅qm \cdot n = p \cdot q .

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Problem 5

  • Day 2

Two circles of radius RR and rr , with R>rR>r , are tangent to each other externally. The sides adjacent to the base of an isosceles triangle are common tangents to these circles. The base of the triangle is tangent to the circle of the greater radius. Determine the length of the base of the triangle.

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Problem 6

  • Day 2

Let (an)(a_n) be defined by: a1=2,an+1=an3−an+1a_1 = 2, a_{n+1} = a_n^3 - a_n + 1 Consider positive integers n,pn,p , where pp is an odd prime. Prove that if p∣anp | a_n , then p>np > n .

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