olymmath

KZ-MO 2004 Problem 6

    The sequence of integers a1a_1 , a2a_2 , …\dots is defined as follows: a1=1a_1 = 1 and n>1n> 1 , an+1a_ {n + 1} is the smallest integer greater than ana_n and such, that ai+aj≠3aka_i + a_j \neq 3a_k for any i,ji, j and kk from {1,2,…,n+1}\{1, 2, \dots, n + 1 \} are not necessarily different. Define a2004a_ {2004} .

    Dataset text AI-MO AoPS. Quoted with source.

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