olymmath

KURSCHAK 1985 Problem 2

    For every n∈Nn\in\mathbb{N} , define the power sum of nn as follows. For every prime divisor pp of nn , consider the largest positive integer kk for which pk≤np^k\le n , and sum up all the pkp^k 's. (For instance, the power sum of 100100 is 26+52=892^6+5^2=89 .) Prove that the power sum of nn is larger than nn for infinitely many positive integers nn .

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