olymmath

KURSCHAK 1977 Problem 2

    ABCABC is a triangle with orthocenter HH . The median from AA meets the circumcircle again at A1A_1 , and A2A_2 is the reflection of A1A_1 in the midpoint of BCBC . The points B2B_2 and C2C_2 are defined similarly. Show that HH , A2A_2 , B2B_2 and C2C_2 lie on a circle. Image

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator kurschak/1977/p2 · Tag KA0YY3JV65 · Edit this page on GitHub · Keys: j next, k previous