olymmath

KURSCHAK 1971

Kürschák Competition 1971.

Other problems

Problem 1

A straight line cuts the side ABAB of the triangle ABCABC at C1C_1 , the side ACAC at B1B_1 and the line BCBC at A1A_1 . C2C_2 is the reflection of C1C_1 in the midpoint of ABAB , and B2B_2 is the reflection of B1B_1 in the midpoint of ACAC . The lines B2C2B_2C_2 and BCBC intersect at A2A_2 . Prove that senB1A1CsenC2A2B=B2C2B1C1\frac{sen B_1A_1C}{sen C_2A_2B} = \frac{B_2C_2}{B_1C_1} Image

Problem 2

Given any 2222 points in the plane, no three collinear. Show that the points can be divided into 1111 pairs, so that the 1111 line segments defined by the pairs have at least five different intersections

Problem 3

There are 3030 boxes each with a unique key. The keys are randomly arranged in the boxes, so that each box contains just one key and the boxes are locked. Two boxes are broken open, thus releasing two keys. What is the probability that the remaining boxes can be opened without forcing them?