olymmath

FKMO 2022

Final Korean Mathematical Olympiad 2022.

Other problems

Problem 2

There are nn boxes A1,...,AnA_1, ..., A_n with non-negative number of pebbles inside it(so it can be empty). Let ana_n be the number of pebbles in the box AnA_n . There are total 3n3n pebbles in the boxes. From now on, Alice plays the following operation.

In each operation, Alice choose one of these boxes which is non-empty. Then she divide this pebbles into nn group such that difference of number of pebbles in any two group is at most 1, and put these nn group of pebbles into nn boxes one by one. This continues until only one box has all the pebbles, and the rest of them are empty. And when it's over, define LengthLength as the total number of operations done by Alice.

Let f(a1,...,an)f(a_1, ..., a_n) be the smallest value of LengthLength among all the possible operations on (a1,...,an)(a_1, ..., a_n) . Find the maximum possible value of f(a1,...,an)f(a_1, ..., a_n) among all the ordered pair (a1,...,an)(a_1, ..., a_n) , and find all the ordered pair (a1,...,an)(a_1, ..., a_n) that equality holds.

Problem 3

A function g ⁣:R→Rg \colon \mathbb{R} \to \mathbb{R} is given such that its range is a finite set. Find all functions f ⁣:R→Rf \colon \mathbb{R} \to \mathbb{R} that satisfies 2f(x+g(y))=f(2g(x)+y)+f(x+3g(y))2f(x+g(y))=f(2g(x)+y)+f(x+3g(y)) for all x,y∈Rx, y \in \mathbb{R} .

Problem 4

Let ABCABC be a scalene triangle with incenter II and let AIAI meet the circumcircle of triangle ABCABC again at MM . The incircle ω\omega of triangle ABCABC is tangent to sides AB,ACAB, AC at D,ED, E , respectively. Let OO be the circumcenter of triangle BDEBDE and let LL be the intersection of ω\omega and the altitude from AA to BCBC so that AA and LL lie on the same side with respect to DEDE . Denote by Ω\Omega a circle centered at OO and passing through LL , and let ALAL meet Ω\Omega again at NN .

Prove that the lines LDLD and MBMB meet on the circumcircle of triangle LNELNE .

Problem 5

Find all positive integers mm such that there exists integers xx and yy that satisfies m∣x2+11y2+2022.m \mid x^2+11y^2+2022.

Problem 6

Set XX is called fancy if it satisfies all of the following conditions:

  • The number of elements of XX is 20222022 .
  • Each element of XX is a closed interval contained in [0,1][0, 1] .
  • For any real number r∈[0,1]r \in [0, 1] , the number of elements of XX containing rr is less than or equal to 10111011 .

For fancy sets A,BA, B , and intervals I∈A,J∈BI \in A, J \in B , denote by n(A,B)n(A, B) the number of pairs (I,J)(I, J) such that I∩J≠∅I \cap J \neq \emptyset . Determine the maximum value of n(A,B)n(A, B) .