olymmath

JBMO 2006 Problem 2

  • Paper

The triangle ABCABC is isosceles with AB=ACAB=AC , and ∠BAC<60∘\angle{BAC}<60^{\circ} . The points DD and EE are chosen on the side ACAC such that, EB=EDEB=ED , and ∠ABD≡∠CBE\angle{ABD}\equiv\angle{CBE} . Denote by OO the intersection point between the internal bisectors of the angles ∠BDC\angle{BDC} and ∠ACB\angle{ACB} . Compute ∠COD\angle{COD} .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator jbmo/2006/p2 · Tag V1T9Y4GYM1 · Edit this page on GitHub · Keys: j next, k previous